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53.3=2x^2/0.4-x
We move all terms to the left:
53.3-(2x^2/0.4-x)=0
Domain of the equation: 0.4-x)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
-x)!=-0.4
x!=-0.4/1
x!=-0.4
x∈R
-2x^2/0.4+x+53.3=0
We multiply all the terms by the denominator
-2x^2+x*0.4+(53.3)*0.4=0
We add all the numbers together, and all the variables
-2x^2+x*0.4+21.32=0
Wy multiply elements
-2x^2+0.4x+21.32=0
a = -2; b = 0.4; c = +21.32;
Δ = b2-4ac
Δ = 0.42-4·(-2)·21.32
Δ = 170.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-\sqrt{170.72}}{2*-2}=\frac{-0.4-\sqrt{170.72}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+\sqrt{170.72}}{2*-2}=\frac{-0.4+\sqrt{170.72}}{-4} $
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